Flip Game
Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 46519 | Accepted: 19915 |
Description
Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the other one is black and each piece is lying either it's black or white side up. Each round you flip 3 to 5 pieces, thus changing the color of their upper side from black to white and vice versa. The pieces to be flipped are chosen every round according to the following rules:
- Choose any one of the 16 pieces.
- Flip the chosen piece and also all adjacent pieces to the left, to the right, to the top, and to the bottom of the chosen piece (if there are any).
Input
The input consists of 4 lines with 4 characters "w" or "b" each that denote game field position.
Output
Write to the output file a single integer number - the minimum number of rounds needed to achieve the goal of the game from the given position. If the goal is initially achieved, then write 0. If it's impossible to achieve the goal, then write the word "Impossible" (without quotes).
Sample Input
bwwbbbwbbwwbbwww
Sample Output
4 题意:给你一个4*4的棋盘,黑棋是‘b’,白棋是‘w’,问最少翻转多少次,可以使棋盘颜色统一。棋子有黑白两面可以翻转,翻转一个棋子,周围的棋子都要翻转。 思路:《算法竞赛入门经典》上提到枚举子集的方法之一---位向量法。这种方法就是把棋盘所有可能的翻转子集情况枚举一遍,如果在翻转过程中,棋盘颜色得以统一,就将现在的步数与最小值进行比较,如果小于最小值,就更新它。
#include#define inf 0x3f3f3f3fint map[5][5],min,n;int Check(int map[][5])//检查棋盘颜色是否统一 { int i,j; for(i = 0; i < 4; i ++) for(j = 0; j < 4; j ++) if(map[0][0] != map[i][j]) return 0; return 1;}void Reverse(int num)//翻转棋子 { int x,y; x = num/4; y = num%4; map[x][y]=!map[x][y]; if(x>0) map[x-1][y]=!map[x-1][y]; if(x<3) map[x+1][y]=!map[x+1][y]; if(y>0) map[x][y-1]=!map[x][y-1]; if(y<3) map[x][y+1]=!map[x][y+1]; return;}void dfs(int num,int step){ if(Check(map)) { if(step < min) min = step; return; } if(num >= n) return; dfs(num+1,step); Reverse(num);//翻转棋子 dfs(num+1,step+1);//step记录已经翻转过的棋子 Reverse(num);//回溯 }int main(){ int i,j; char ch; for(i = 0; i < 4; i ++) { for(j = 0; j < 4; j ++) { scanf("%c",&ch); if(ch == 'b')//构建棋盘 map[i][j] = 0; else map[i][j] = 1; } getchar(); } n = 16; min = inf; dfs(0,0); if(min == inf) printf("Impossible\n"); else printf("%d\n",min); return 0;}